Solve 12x + 1 = 229
The solution of 12x + 1 = 229 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 1 = 229\ \Rightarrow\ x = 19 \]
\[ 12x + 1 = 229 \]
\[ 12x + 1 - 1 = 229 - 1 \ \Rightarrow\ 12x = 228 \]
\[ \frac{12x}{12} = \frac{228}{12} \ \Rightarrow\ x = 19 \]
\[ 12\cdot19 + 1 = 228 + 1 = 229 \checkmark \]Trying values of x in 12x + 1 = 229
| x | 12x + 1 | Equals 229? |
|---|---|---|
| 17 | 205 | no |
| 18 | 217 | no |
| 19 | 229 | yes |
| 20 | 241 | no |
| 21 | 253 | no |
Questions
What is x in 12x + 1 = 229?
The solution of 12x + 1 = 229 is x = 19.
How do you solve 12x + 1 = 229?
Subtract 1 from both sides to get 12x = 228, then divide both sides by 12 to get x = 19.
How do I check the answer?
Replace x by 19: 12(19) + 1 = 229, which is 229.