Solve 12x + 1 = 193
The solution of 12x + 1 = 193 is x = 16.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 12:
- 4
Check: put x = 16 back into the equation.
LaTeX source of the formulas on this page
\[ 12x + 1 = 193\ \Rightarrow\ x = 16 \]
\[ 12x + 1 = 193 \]
\[ 12x + 1 - 1 = 193 - 1 \ \Rightarrow\ 12x = 192 \]
\[ \frac{12x}{12} = \frac{192}{12} \ \Rightarrow\ x = 16 \]
\[ 12\cdot16 + 1 = 192 + 1 = 193 \checkmark \]Trying values of x in 12x + 1 = 193
| x | 12x + 1 | Equals 193? |
|---|---|---|
| 14 | 169 | no |
| 15 | 181 | no |
| 16 | 193 | yes |
| 17 | 205 | no |
| 18 | 217 | no |
Questions
What is x in 12x + 1 = 193?
The solution of 12x + 1 = 193 is x = 16.
How do you solve 12x + 1 = 193?
Subtract 1 from both sides to get 12x = 192, then divide both sides by 12 to get x = 16.
How do I check the answer?
Replace x by 16: 12(16) + 1 = 193, which is 193.