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Solve 12x āˆ’ 5 = 223

The solution of 12x āˆ’ 5 = 223 is x = 19.

The lines y = 12x āˆ’ 5 and y = 223 meet at x = 19141618202224140160180200220240260280300x = 19y = 12x āˆ’ 5y = 223
The lines y = 12x āˆ’ 5 and y = 223 meet at x = 19. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’5=22312x - 5 = 223
  2. 2

    Add 5 to both sides:

    12xāˆ’5+5=223+5 ⇒ 12x=22812x - 5 + 5 = 223 + 5 \ \Rightarrow\ 12x = 228
  3. 3

    Divide both sides by 12:

    12x12=22812 ⇒ x=19\frac{12x}{12} = \frac{228}{12} \ \Rightarrow\ x = 19
  4. 4

    Check: put x = 19 back into the equation.

    12ā‹…19āˆ’5=228āˆ’5=223āœ“12\cdot19 - 5 = 228 - 5 = 223 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 5 = 223\ \Rightarrow\ x = 19 \]
\[ 12x - 5 = 223 \]
\[ 12x - 5 + 5 = 223 + 5 \ \Rightarrow\ 12x = 228 \]
\[ \frac{12x}{12} = \frac{228}{12} \ \Rightarrow\ x = 19 \]
\[ 12\cdot19 - 5 = 228 - 5 = 223 \checkmark \]

Trying values of x in 12x āˆ’ 5 = 223

x12x āˆ’ 5Equals 223?
17199no
18211no
19223yes
20235no
21247no

Questions

What is x in 12x āˆ’ 5 = 223?

The solution of 12x āˆ’ 5 = 223 is x = 19.

How do you solve 12x āˆ’ 5 = 223?

Add 5 to both sides to get 12x = 228, then divide both sides by 12 to get x = 19.

How do I check the answer?

Replace x by 19: 12(19) āˆ’ 5 = 223, which is 223.

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    Solve 12x āˆ’ 5 = 223: x = 19 (steps and check) | WordGPT