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Solve 12x āˆ’ 3 = āˆ’75

The solution of 12x āˆ’ 3 = āˆ’75 is x = -6.

The lines y = 12x āˆ’ 3 and y = -75 meet at x = -6-12-10-8-6-4-2-160-140-120-100-80-60-40-20x = -6y = 12x āˆ’ 3y = -75
The lines y = 12x āˆ’ 3 and y = -75 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’3=āˆ’7512x - 3 = -75
  2. 2

    Add 3 to both sides:

    12xāˆ’3+3=āˆ’75+3 ⇒ 12x=āˆ’7212x - 3 + 3 = -75 + 3 \ \Rightarrow\ 12x = -72
  3. 3

    Divide both sides by 12:

    12x12=āˆ’7212 ⇒ x=āˆ’6\frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    12ā‹…(āˆ’6)āˆ’3=āˆ’72āˆ’3=āˆ’75āœ“12\cdot(-6) - 3 = -72 - 3 = -75 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 3 = -75\ \Rightarrow\ x = -6 \]
\[ 12x - 3 = -75 \]
\[ 12x - 3 + 3 = -75 + 3 \ \Rightarrow\ 12x = -72 \]
\[ \frac{12x}{12} = \frac{-72}{12} \ \Rightarrow\ x = -6 \]
\[ 12\cdot(-6) - 3 = -72 - 3 = -75 \checkmark \]

Trying values of x in 12x āˆ’ 3 = āˆ’75

x12x āˆ’ 3Equals -75?
-8-99no
-7-87no
-6-75yes
-5-63no
-4-51no

Questions

What is x in 12x āˆ’ 3 = āˆ’75?

The solution of 12x āˆ’ 3 = āˆ’75 is x = -6.

How do you solve 12x āˆ’ 3 = āˆ’75?

Add 3 to both sides to get 12x = -72, then divide both sides by 12 to get x = -6.

How do I check the answer?

Replace x by -6: 12(-6) āˆ’ 3 = -75, which is -75.

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    Solve 12x āˆ’ 3 = āˆ’75: x = -6 (steps and check) | WordGPT