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Solve 12x āˆ’ 15 = āˆ’63

The solution of 12x āˆ’ 15 = āˆ’63 is x = -4.

The lines y = 12x āˆ’ 15 and y = -63 meet at x = -4-10-8-6-4-22-140-120-100-80-60-40-2020x = -4y = 12x āˆ’ 15y = -63
The lines y = 12x āˆ’ 15 and y = -63 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’15=āˆ’6312x - 15 = -63
  2. 2

    Add 15 to both sides:

    12xāˆ’15+15=āˆ’63+15 ⇒ 12x=āˆ’4812x - 15 + 15 = -63 + 15 \ \Rightarrow\ 12x = -48
  3. 3

    Divide both sides by 12:

    12x12=āˆ’4812 ⇒ x=āˆ’4\frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    12ā‹…(āˆ’4)āˆ’15=āˆ’48āˆ’15=āˆ’63āœ“12\cdot(-4) - 15 = -48 - 15 = -63 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 15 = -63\ \Rightarrow\ x = -4 \]
\[ 12x - 15 = -63 \]
\[ 12x - 15 + 15 = -63 + 15 \ \Rightarrow\ 12x = -48 \]
\[ \frac{12x}{12} = \frac{-48}{12} \ \Rightarrow\ x = -4 \]
\[ 12\cdot(-4) - 15 = -48 - 15 = -63 \checkmark \]

Trying values of x in 12x āˆ’ 15 = āˆ’63

x12x āˆ’ 15Equals -63?
-6-87no
-5-75no
-4-63yes
-3-51no
-2-39no

Questions

What is x in 12x āˆ’ 15 = āˆ’63?

The solution of 12x āˆ’ 15 = āˆ’63 is x = -4.

How do you solve 12x āˆ’ 15 = āˆ’63?

Add 15 to both sides to get 12x = -48, then divide both sides by 12 to get x = -4.

How do I check the answer?

Replace x by -4: 12(-4) āˆ’ 15 = -63, which is -63.

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    Solve 12x āˆ’ 15 = āˆ’63: x = -4 (steps and check) | WordGPT