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Solve 12x āˆ’ 14 = 118

The solution of 12x āˆ’ 14 = 118 is x = 11.

The lines y = 12x āˆ’ 14 and y = 118 meet at x = 116810121416406080100120140160180200x = 11y = 12x āˆ’ 14y = 118
The lines y = 12x āˆ’ 14 and y = 118 meet at x = 11. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’14=11812x - 14 = 118
  2. 2

    Add 14 to both sides:

    12xāˆ’14+14=118+14 ⇒ 12x=13212x - 14 + 14 = 118 + 14 \ \Rightarrow\ 12x = 132
  3. 3

    Divide both sides by 12:

    12x12=13212 ⇒ x=11\frac{12x}{12} = \frac{132}{12} \ \Rightarrow\ x = 11
  4. 4

    Check: put x = 11 back into the equation.

    12ā‹…11āˆ’14=132āˆ’14=118āœ“12\cdot11 - 14 = 132 - 14 = 118 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 14 = 118\ \Rightarrow\ x = 11 \]
\[ 12x - 14 = 118 \]
\[ 12x - 14 + 14 = 118 + 14 \ \Rightarrow\ 12x = 132 \]
\[ \frac{12x}{12} = \frac{132}{12} \ \Rightarrow\ x = 11 \]
\[ 12\cdot11 - 14 = 132 - 14 = 118 \checkmark \]

Trying values of x in 12x āˆ’ 14 = 118

x12x āˆ’ 14Equals 118?
994no
10106no
11118yes
12130no
13142no

Questions

What is x in 12x āˆ’ 14 = 118?

The solution of 12x āˆ’ 14 = 118 is x = 11.

How do you solve 12x āˆ’ 14 = 118?

Add 14 to both sides to get 12x = 132, then divide both sides by 12 to get x = 11.

How do I check the answer?

Replace x by 11: 12(11) āˆ’ 14 = 118, which is 118.

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