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Solve 12x āˆ’ 11 = 109

The solution of 12x āˆ’ 11 = 109 is x = 10.

The lines y = 12x āˆ’ 11 and y = 109 meet at x = 1046810121416406080100120140160180x = 10y = 12x āˆ’ 11y = 109
The lines y = 12x āˆ’ 11 and y = 109 meet at x = 10. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    12xāˆ’11=10912x - 11 = 109
  2. 2

    Add 11 to both sides:

    12xāˆ’11+11=109+11 ⇒ 12x=12012x - 11 + 11 = 109 + 11 \ \Rightarrow\ 12x = 120
  3. 3

    Divide both sides by 12:

    12x12=12012 ⇒ x=10\frac{12x}{12} = \frac{120}{12} \ \Rightarrow\ x = 10
  4. 4

    Check: put x = 10 back into the equation.

    12ā‹…10āˆ’11=120āˆ’11=109āœ“12\cdot10 - 11 = 120 - 11 = 109 \checkmark
LaTeX source of the formulas on this page
\[ 12x - 11 = 109\ \Rightarrow\ x = 10 \]
\[ 12x - 11 = 109 \]
\[ 12x - 11 + 11 = 109 + 11 \ \Rightarrow\ 12x = 120 \]
\[ \frac{12x}{12} = \frac{120}{12} \ \Rightarrow\ x = 10 \]
\[ 12\cdot10 - 11 = 120 - 11 = 109 \checkmark \]

Trying values of x in 12x āˆ’ 11 = 109

x12x āˆ’ 11Equals 109?
885no
997no
10109yes
11121no
12133no

Questions

What is x in 12x āˆ’ 11 = 109?

The solution of 12x āˆ’ 11 = 109 is x = 10.

How do you solve 12x āˆ’ 11 = 109?

Add 11 to both sides to get 12x = 120, then divide both sides by 12 to get x = 10.

How do I check the answer?

Replace x by 10: 12(10) āˆ’ 11 = 109, which is 109.

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