Solve 11x + 7 = ā48
The solution of 11x + 7 = ā48 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 7 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 7 = -48\ \Rightarrow\ x = -5 \]
\[ 11x + 7 = -48 \]
\[ 11x + 7 - 7 = -48 - 7 \ \Rightarrow\ 11x = -55 \]
\[ \frac{11x}{11} = \frac{-55}{11} \ \Rightarrow\ x = -5 \]
\[ 11\cdot(-5) + 7 = -55 + 7 = -48 \checkmark \]Trying values of x in 11x + 7 = ā48
| x | 11x + 7 | Equals -48? |
|---|---|---|
| -7 | -70 | no |
| -6 | -59 | no |
| -5 | -48 | yes |
| -4 | -37 | no |
| -3 | -26 | no |
Questions
What is x in 11x + 7 = ā48?
The solution of 11x + 7 = ā48 is x = -5.
How do you solve 11x + 7 = ā48?
Subtract 7 from both sides to get 11x = -55, then divide both sides by 11 to get x = -5.
How do I check the answer?
Replace x by -5: 11(-5) + 7 = -48, which is -48.