Solve 11x + 5 = ā94
The solution of 11x + 5 = ā94 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 5 = -94\ \Rightarrow\ x = -9 \]
\[ 11x + 5 = -94 \]
\[ 11x + 5 - 5 = -94 - 5 \ \Rightarrow\ 11x = -99 \]
\[ \frac{11x}{11} = \frac{-99}{11} \ \Rightarrow\ x = -9 \]
\[ 11\cdot(-9) + 5 = -99 + 5 = -94 \checkmark \]Trying values of x in 11x + 5 = ā94
| x | 11x + 5 | Equals -94? |
|---|---|---|
| -11 | -116 | no |
| -10 | -105 | no |
| -9 | -94 | yes |
| -8 | -83 | no |
| -7 | -72 | no |
Questions
What is x in 11x + 5 = ā94?
The solution of 11x + 5 = ā94 is x = -9.
How do you solve 11x + 5 = ā94?
Subtract 5 from both sides to get 11x = -99, then divide both sides by 11 to get x = -9.
How do I check the answer?
Replace x by -9: 11(-9) + 5 = -94, which is -94.