Solve 11x + 5 = 27
The solution of 11x + 5 = 27 is x = 2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 2 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 5 = 27\ \Rightarrow\ x = 2 \]
\[ 11x + 5 = 27 \]
\[ 11x + 5 - 5 = 27 - 5 \ \Rightarrow\ 11x = 22 \]
\[ \frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2 \]
\[ 11\cdot2 + 5 = 22 + 5 = 27 \checkmark \]Trying values of x in 11x + 5 = 27
| x | 11x + 5 | Equals 27? |
|---|---|---|
| 0 | 5 | no |
| 1 | 16 | no |
| 2 | 27 | yes |
| 3 | 38 | no |
| 4 | 49 | no |
Questions
What is x in 11x + 5 = 27?
The solution of 11x + 5 = 27 is x = 2.
How do you solve 11x + 5 = 27?
Subtract 5 from both sides to get 11x = 22, then divide both sides by 11 to get x = 2.
How do I check the answer?
Replace x by 2: 11(2) + 5 = 27, which is 27.