Solve 11x + 5 = 192
The solution of 11x + 5 = 192 is x = 17.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 5 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 17 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 5 = 192\ \Rightarrow\ x = 17 \]
\[ 11x + 5 = 192 \]
\[ 11x + 5 - 5 = 192 - 5 \ \Rightarrow\ 11x = 187 \]
\[ \frac{11x}{11} = \frac{187}{11} \ \Rightarrow\ x = 17 \]
\[ 11\cdot17 + 5 = 187 + 5 = 192 \checkmark \]Trying values of x in 11x + 5 = 192
| x | 11x + 5 | Equals 192? |
|---|---|---|
| 15 | 170 | no |
| 16 | 181 | no |
| 17 | 192 | yes |
| 18 | 203 | no |
| 19 | 214 | no |
Questions
What is x in 11x + 5 = 192?
The solution of 11x + 5 = 192 is x = 17.
How do you solve 11x + 5 = 192?
Subtract 5 from both sides to get 11x = 187, then divide both sides by 11 to get x = 17.
How do I check the answer?
Replace x by 17: 11(17) + 5 = 192, which is 192.