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Solve 11x + 4 = āˆ’40

The solution of 11x + 4 = āˆ’40 is x = -4.

The lines y = 11x + 4 and y = -40 meet at x = -4-10-8-6-4-22-100-80-60-40-2020x = -4y = 11x + 4y = -40
The lines y = 11x + 4 and y = -40 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+4=āˆ’4011x + 4 = -40
  2. 2

    Subtract 4 from both sides:

    11x+4āˆ’4=āˆ’40āˆ’4 ⇒ 11x=āˆ’4411x + 4 - 4 = -40 - 4 \ \Rightarrow\ 11x = -44
  3. 3

    Divide both sides by 11:

    11x11=āˆ’4411 ⇒ x=āˆ’4\frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    11ā‹…(āˆ’4)+4=āˆ’44+4=āˆ’40āœ“11\cdot(-4) + 4 = -44 + 4 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 4 = -40\ \Rightarrow\ x = -4 \]
\[ 11x + 4 = -40 \]
\[ 11x + 4 - 4 = -40 - 4 \ \Rightarrow\ 11x = -44 \]
\[ \frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4 \]
\[ 11\cdot(-4) + 4 = -44 + 4 = -40 \checkmark \]

Trying values of x in 11x + 4 = āˆ’40

x11x + 4Equals -40?
-6-62no
-5-51no
-4-40yes
-3-29no
-2-18no

Questions

What is x in 11x + 4 = āˆ’40?

The solution of 11x + 4 = āˆ’40 is x = -4.

How do you solve 11x + 4 = āˆ’40?

Subtract 4 from both sides to get 11x = -44, then divide both sides by 11 to get x = -4.

How do I check the answer?

Replace x by -4: 11(-4) + 4 = -40, which is -40.

Similar equations

    Solve 11x + 4 = āˆ’40: x = -4 (steps and check) | WordGPT