Solve 11x + 4 = 202
The solution of 11x + 4 = 202 is x = 18.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 4 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 18 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 4 = 202\ \Rightarrow\ x = 18 \]
\[ 11x + 4 = 202 \]
\[ 11x + 4 - 4 = 202 - 4 \ \Rightarrow\ 11x = 198 \]
\[ \frac{11x}{11} = \frac{198}{11} \ \Rightarrow\ x = 18 \]
\[ 11\cdot18 + 4 = 198 + 4 = 202 \checkmark \]Trying values of x in 11x + 4 = 202
| x | 11x + 4 | Equals 202? |
|---|---|---|
| 16 | 180 | no |
| 17 | 191 | no |
| 18 | 202 | yes |
| 19 | 213 | no |
| 20 | 224 | no |
Questions
What is x in 11x + 4 = 202?
The solution of 11x + 4 = 202 is x = 18.
How do you solve 11x + 4 = 202?
Subtract 4 from both sides to get 11x = 198, then divide both sides by 11 to get x = 18.
How do I check the answer?
Replace x by 18: 11(18) + 4 = 202, which is 202.