Solve 11x + 3 = ā19
The solution of 11x + 3 = ā19 is x = -2.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 3 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -2 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 3 = -19\ \Rightarrow\ x = -2 \]
\[ 11x + 3 = -19 \]
\[ 11x + 3 - 3 = -19 - 3 \ \Rightarrow\ 11x = -22 \]
\[ \frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2 \]
\[ 11\cdot(-2) + 3 = -22 + 3 = -19 \checkmark \]Trying values of x in 11x + 3 = ā19
| x | 11x + 3 | Equals -19? |
|---|---|---|
| -4 | -41 | no |
| -3 | -30 | no |
| -2 | -19 | yes |
| -1 | -8 | no |
| 0 | 3 | no |
Questions
What is x in 11x + 3 = ā19?
The solution of 11x + 3 = ā19 is x = -2.
How do you solve 11x + 3 = ā19?
Subtract 3 from both sides to get 11x = -22, then divide both sides by 11 to get x = -2.
How do I check the answer?
Replace x by -2: 11(-2) + 3 = -19, which is -19.