Solve 11x + 2 = ā97
The solution of 11x + 2 = ā97 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 2 = -97\ \Rightarrow\ x = -9 \]
\[ 11x + 2 = -97 \]
\[ 11x + 2 - 2 = -97 - 2 \ \Rightarrow\ 11x = -99 \]
\[ \frac{11x}{11} = \frac{-99}{11} \ \Rightarrow\ x = -9 \]
\[ 11\cdot(-9) + 2 = -99 + 2 = -97 \checkmark \]Trying values of x in 11x + 2 = ā97
| x | 11x + 2 | Equals -97? |
|---|---|---|
| -11 | -119 | no |
| -10 | -108 | no |
| -9 | -97 | yes |
| -8 | -86 | no |
| -7 | -75 | no |
Questions
What is x in 11x + 2 = ā97?
The solution of 11x + 2 = ā97 is x = -9.
How do you solve 11x + 2 = ā97?
Subtract 2 from both sides to get 11x = -99, then divide both sides by 11 to get x = -9.
How do I check the answer?
Replace x by -9: 11(-9) + 2 = -97, which is -97.