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Solve 11x + 2 = āˆ’64

The solution of 11x + 2 = āˆ’64 is x = -6.

The lines y = 11x + 2 and y = -64 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 11x + 2y = -64
The lines y = 11x + 2 and y = -64 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    11x+2=āˆ’6411x + 2 = -64
  2. 2

    Subtract 2 from both sides:

    11x+2āˆ’2=āˆ’64āˆ’2 ⇒ 11x=āˆ’6611x + 2 - 2 = -64 - 2 \ \Rightarrow\ 11x = -66
  3. 3

    Divide both sides by 11:

    11x11=āˆ’6611 ⇒ x=āˆ’6\frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    11ā‹…(āˆ’6)+2=āˆ’66+2=āˆ’64āœ“11\cdot(-6) + 2 = -66 + 2 = -64 \checkmark
LaTeX source of the formulas on this page
\[ 11x + 2 = -64\ \Rightarrow\ x = -6 \]
\[ 11x + 2 = -64 \]
\[ 11x + 2 - 2 = -64 - 2 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) + 2 = -66 + 2 = -64 \checkmark \]

Trying values of x in 11x + 2 = āˆ’64

x11x + 2Equals -64?
-8-86no
-7-75no
-6-64yes
-5-53no
-4-42no

Questions

What is x in 11x + 2 = āˆ’64?

The solution of 11x + 2 = āˆ’64 is x = -6.

How do you solve 11x + 2 = āˆ’64?

Subtract 2 from both sides to get 11x = -66, then divide both sides by 11 to get x = -6.

How do I check the answer?

Replace x by -6: 11(-6) + 2 = -64, which is -64.

Similar equations

    Solve 11x + 2 = āˆ’64: x = -6 (steps and check) | WordGPT