Solve 11x + 15 = ā95
The solution of 11x + 15 = ā95 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 15 = -95\ \Rightarrow\ x = -10 \]
\[ 11x + 15 = -95 \]
\[ 11x + 15 - 15 = -95 - 15 \ \Rightarrow\ 11x = -110 \]
\[ \frac{11x}{11} = \frac{-110}{11} \ \Rightarrow\ x = -10 \]
\[ 11\cdot(-10) + 15 = -110 + 15 = -95 \checkmark \]Trying values of x in 11x + 15 = ā95
| x | 11x + 15 | Equals -95? |
|---|---|---|
| -12 | -117 | no |
| -11 | -106 | no |
| -10 | -95 | yes |
| -9 | -84 | no |
| -8 | -73 | no |
Questions
What is x in 11x + 15 = ā95?
The solution of 11x + 15 = ā95 is x = -10.
How do you solve 11x + 15 = ā95?
Subtract 15 from both sides to get 11x = -110, then divide both sides by 11 to get x = -10.
How do I check the answer?
Replace x by -10: 11(-10) + 15 = -95, which is -95.