Solve 11x + 15 = ā18
The solution of 11x + 15 = ā18 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 15 = -18\ \Rightarrow\ x = -3 \]
\[ 11x + 15 = -18 \]
\[ 11x + 15 - 15 = -18 - 15 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) + 15 = -33 + 15 = -18 \checkmark \]Trying values of x in 11x + 15 = ā18
| x | 11x + 15 | Equals -18? |
|---|---|---|
| -5 | -40 | no |
| -4 | -29 | no |
| -3 | -18 | yes |
| -2 | -7 | no |
| -1 | 4 | no |
Questions
What is x in 11x + 15 = ā18?
The solution of 11x + 15 = ā18 is x = -3.
How do you solve 11x + 15 = ā18?
Subtract 15 from both sides to get 11x = -33, then divide both sides by 11 to get x = -3.
How do I check the answer?
Replace x by -3: 11(-3) + 15 = -18, which is -18.