Solve 11x + 15 = 147
The solution of 11x + 15 = 147 is x = 12.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 12 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 15 = 147\ \Rightarrow\ x = 12 \]
\[ 11x + 15 = 147 \]
\[ 11x + 15 - 15 = 147 - 15 \ \Rightarrow\ 11x = 132 \]
\[ \frac{11x}{11} = \frac{132}{11} \ \Rightarrow\ x = 12 \]
\[ 11\cdot12 + 15 = 132 + 15 = 147 \checkmark \]Trying values of x in 11x + 15 = 147
| x | 11x + 15 | Equals 147? |
|---|---|---|
| 10 | 125 | no |
| 11 | 136 | no |
| 12 | 147 | yes |
| 13 | 158 | no |
| 14 | 169 | no |
Questions
What is x in 11x + 15 = 147?
The solution of 11x + 15 = 147 is x = 12.
How do you solve 11x + 15 = 147?
Subtract 15 from both sides to get 11x = 132, then divide both sides by 11 to get x = 12.
How do I check the answer?
Replace x by 12: 11(12) + 15 = 147, which is 147.