Solve 11x + 12 = ā98
The solution of 11x + 12 = ā98 is x = -10.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -10 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 12 = -98\ \Rightarrow\ x = -10 \]
\[ 11x + 12 = -98 \]
\[ 11x + 12 - 12 = -98 - 12 \ \Rightarrow\ 11x = -110 \]
\[ \frac{11x}{11} = \frac{-110}{11} \ \Rightarrow\ x = -10 \]
\[ 11\cdot(-10) + 12 = -110 + 12 = -98 \checkmark \]Trying values of x in 11x + 12 = ā98
| x | 11x + 12 | Equals -98? |
|---|---|---|
| -12 | -120 | no |
| -11 | -109 | no |
| -10 | -98 | yes |
| -9 | -87 | no |
| -8 | -76 | no |
Questions
What is x in 11x + 12 = ā98?
The solution of 11x + 12 = ā98 is x = -10.
How do you solve 11x + 12 = ā98?
Subtract 12 from both sides to get 11x = -110, then divide both sides by 11 to get x = -10.
How do I check the answer?
Replace x by -10: 11(-10) + 12 = -98, which is -98.