Solve 11x + 12 = 221
The solution of 11x + 12 = 221 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 12 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 12 = 221\ \Rightarrow\ x = 19 \]
\[ 11x + 12 = 221 \]
\[ 11x + 12 - 12 = 221 - 12 \ \Rightarrow\ 11x = 209 \]
\[ \frac{11x}{11} = \frac{209}{11} \ \Rightarrow\ x = 19 \]
\[ 11\cdot19 + 12 = 209 + 12 = 221 \checkmark \]Trying values of x in 11x + 12 = 221
| x | 11x + 12 | Equals 221? |
|---|---|---|
| 17 | 199 | no |
| 18 | 210 | no |
| 19 | 221 | yes |
| 20 | 232 | no |
| 21 | 243 | no |
Questions
What is x in 11x + 12 = 221?
The solution of 11x + 12 = 221 is x = 19.
How do you solve 11x + 12 = 221?
Subtract 12 from both sides to get 11x = 209, then divide both sides by 11 to get x = 19.
How do I check the answer?
Replace x by 19: 11(19) + 12 = 221, which is 221.