Solve 11x + 11 = ā88
The solution of 11x + 11 = ā88 is x = -9.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -9 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 11 = -88\ \Rightarrow\ x = -9 \]
\[ 11x + 11 = -88 \]
\[ 11x + 11 - 11 = -88 - 11 \ \Rightarrow\ 11x = -99 \]
\[ \frac{11x}{11} = \frac{-99}{11} \ \Rightarrow\ x = -9 \]
\[ 11\cdot(-9) + 11 = -99 + 11 = -88 \checkmark \]Trying values of x in 11x + 11 = ā88
| x | 11x + 11 | Equals -88? |
|---|---|---|
| -11 | -110 | no |
| -10 | -99 | no |
| -9 | -88 | yes |
| -8 | -77 | no |
| -7 | -66 | no |
Questions
What is x in 11x + 11 = ā88?
The solution of 11x + 11 = ā88 is x = -9.
How do you solve 11x + 11 = ā88?
Subtract 11 from both sides to get 11x = -99, then divide both sides by 11 to get x = -9.
How do I check the answer?
Replace x by -9: 11(-9) + 11 = -88, which is -88.