Solve 11x + 1 = ā32
The solution of 11x + 1 = ā32 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 1 from both sides:
- 3
Divide both sides by 11:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 11x + 1 = -32\ \Rightarrow\ x = -3 \]
\[ 11x + 1 = -32 \]
\[ 11x + 1 - 1 = -32 - 1 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) + 1 = -33 + 1 = -32 \checkmark \]Trying values of x in 11x + 1 = ā32
| x | 11x + 1 | Equals -32? |
|---|---|---|
| -5 | -54 | no |
| -4 | -43 | no |
| -3 | -32 | yes |
| -2 | -21 | no |
| -1 | -10 | no |
Questions
What is x in 11x + 1 = ā32?
The solution of 11x + 1 = ā32 is x = -3.
How do you solve 11x + 1 = ā32?
Subtract 1 from both sides to get 11x = -33, then divide both sides by 11 to get x = -3.
How do I check the answer?
Replace x by -3: 11(-3) + 1 = -32, which is -32.