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Solve 11x āˆ’ 8 = āˆ’52

The solution of 11x āˆ’ 8 = āˆ’52 is x = -4.

The lines y = 11x āˆ’ 8 and y = -52 meet at x = -4-10-8-6-4-22-120-100-80-60-40-2020x = -4y = 11x āˆ’ 8y = -52
The lines y = 11x āˆ’ 8 and y = -52 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’8=āˆ’5211x - 8 = -52
  2. 2

    Add 8 to both sides:

    11xāˆ’8+8=āˆ’52+8 ⇒ 11x=āˆ’4411x - 8 + 8 = -52 + 8 \ \Rightarrow\ 11x = -44
  3. 3

    Divide both sides by 11:

    11x11=āˆ’4411 ⇒ x=āˆ’4\frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    11ā‹…(āˆ’4)āˆ’8=āˆ’44āˆ’8=āˆ’52āœ“11\cdot(-4) - 8 = -44 - 8 = -52 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 8 = -52\ \Rightarrow\ x = -4 \]
\[ 11x - 8 = -52 \]
\[ 11x - 8 + 8 = -52 + 8 \ \Rightarrow\ 11x = -44 \]
\[ \frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4 \]
\[ 11\cdot(-4) - 8 = -44 - 8 = -52 \checkmark \]

Trying values of x in 11x āˆ’ 8 = āˆ’52

x11x āˆ’ 8Equals -52?
-6-74no
-5-63no
-4-52yes
-3-41no
-2-30no

Questions

What is x in 11x āˆ’ 8 = āˆ’52?

The solution of 11x āˆ’ 8 = āˆ’52 is x = -4.

How do you solve 11x āˆ’ 8 = āˆ’52?

Add 8 to both sides to get 11x = -44, then divide both sides by 11 to get x = -4.

How do I check the answer?

Replace x by -4: 11(-4) āˆ’ 8 = -52, which is -52.

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    Solve 11x āˆ’ 8 = āˆ’52: x = -4 (steps and check) | WordGPT