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Solve 11x āˆ’ 7 = āˆ’40

The solution of 11x āˆ’ 7 = āˆ’40 is x = -3.

The lines y = 11x āˆ’ 7 and y = -40 meet at x = -3-8-6-4-22-100-80-60-40-2020x = -3y = 11x āˆ’ 7y = -40
The lines y = 11x āˆ’ 7 and y = -40 meet at x = -3. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’7=āˆ’4011x - 7 = -40
  2. 2

    Add 7 to both sides:

    11xāˆ’7+7=āˆ’40+7 ⇒ 11x=āˆ’3311x - 7 + 7 = -40 + 7 \ \Rightarrow\ 11x = -33
  3. 3

    Divide both sides by 11:

    11x11=āˆ’3311 ⇒ x=āˆ’3\frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3
  4. 4

    Check: put x = -3 back into the equation.

    11ā‹…(āˆ’3)āˆ’7=āˆ’33āˆ’7=āˆ’40āœ“11\cdot(-3) - 7 = -33 - 7 = -40 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 7 = -40\ \Rightarrow\ x = -3 \]
\[ 11x - 7 = -40 \]
\[ 11x - 7 + 7 = -40 + 7 \ \Rightarrow\ 11x = -33 \]
\[ \frac{11x}{11} = \frac{-33}{11} \ \Rightarrow\ x = -3 \]
\[ 11\cdot(-3) - 7 = -33 - 7 = -40 \checkmark \]

Trying values of x in 11x āˆ’ 7 = āˆ’40

x11x āˆ’ 7Equals -40?
-5-62no
-4-51no
-3-40yes
-2-29no
-1-18no

Questions

What is x in 11x āˆ’ 7 = āˆ’40?

The solution of 11x āˆ’ 7 = āˆ’40 is x = -3.

How do you solve 11x āˆ’ 7 = āˆ’40?

Add 7 to both sides to get 11x = -33, then divide both sides by 11 to get x = -3.

How do I check the answer?

Replace x by -3: 11(-3) āˆ’ 7 = -40, which is -40.

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    Solve 11x āˆ’ 7 = āˆ’40: x = -3 (steps and check) | WordGPT