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Solve 11x āˆ’ 7 = 15

The solution of 11x āˆ’ 7 = 15 is x = 2.

The lines y = 11x āˆ’ 7 and y = 15 meet at x = 2-4-22468-60-40-2020406080x = 2y = 11x āˆ’ 7y = 15
The lines y = 11x āˆ’ 7 and y = 15 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’7=1511x - 7 = 15
  2. 2

    Add 7 to both sides:

    11xāˆ’7+7=15+7 ⇒ 11x=2211x - 7 + 7 = 15 + 7 \ \Rightarrow\ 11x = 22
  3. 3

    Divide both sides by 11:

    11x11=2211 ⇒ x=2\frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    11ā‹…2āˆ’7=22āˆ’7=15āœ“11\cdot2 - 7 = 22 - 7 = 15 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 7 = 15\ \Rightarrow\ x = 2 \]
\[ 11x - 7 = 15 \]
\[ 11x - 7 + 7 = 15 + 7 \ \Rightarrow\ 11x = 22 \]
\[ \frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2 \]
\[ 11\cdot2 - 7 = 22 - 7 = 15 \checkmark \]

Trying values of x in 11x āˆ’ 7 = 15

x11x āˆ’ 7Equals 15?
0-7no
14no
215yes
326no
437no

Questions

What is x in 11x āˆ’ 7 = 15?

The solution of 11x āˆ’ 7 = 15 is x = 2.

How do you solve 11x āˆ’ 7 = 15?

Add 7 to both sides to get 11x = 22, then divide both sides by 11 to get x = 2.

How do I check the answer?

Replace x by 2: 11(2) āˆ’ 7 = 15, which is 15.

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