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Solve 11x āˆ’ 6 = āˆ’50

The solution of 11x āˆ’ 6 = āˆ’50 is x = -4.

The lines y = 11x āˆ’ 6 and y = -50 meet at x = -4-10-8-6-4-22-120-100-80-60-40-2020x = -4y = 11x āˆ’ 6y = -50
The lines y = 11x āˆ’ 6 and y = -50 meet at x = -4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’6=āˆ’5011x - 6 = -50
  2. 2

    Add 6 to both sides:

    11xāˆ’6+6=āˆ’50+6 ⇒ 11x=āˆ’4411x - 6 + 6 = -50 + 6 \ \Rightarrow\ 11x = -44
  3. 3

    Divide both sides by 11:

    11x11=āˆ’4411 ⇒ x=āˆ’4\frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4
  4. 4

    Check: put x = -4 back into the equation.

    11ā‹…(āˆ’4)āˆ’6=āˆ’44āˆ’6=āˆ’50āœ“11\cdot(-4) - 6 = -44 - 6 = -50 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 6 = -50\ \Rightarrow\ x = -4 \]
\[ 11x - 6 = -50 \]
\[ 11x - 6 + 6 = -50 + 6 \ \Rightarrow\ 11x = -44 \]
\[ \frac{11x}{11} = \frac{-44}{11} \ \Rightarrow\ x = -4 \]
\[ 11\cdot(-4) - 6 = -44 - 6 = -50 \checkmark \]

Trying values of x in 11x āˆ’ 6 = āˆ’50

x11x āˆ’ 6Equals -50?
-6-72no
-5-61no
-4-50yes
-3-39no
-2-28no

Questions

What is x in 11x āˆ’ 6 = āˆ’50?

The solution of 11x āˆ’ 6 = āˆ’50 is x = -4.

How do you solve 11x āˆ’ 6 = āˆ’50?

Add 6 to both sides to get 11x = -44, then divide both sides by 11 to get x = -4.

How do I check the answer?

Replace x by -4: 11(-4) āˆ’ 6 = -50, which is -50.

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    Solve 11x āˆ’ 6 = āˆ’50: x = -4 (steps and check) | WordGPT