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Solve 11x āˆ’ 6 = āˆ’28

The solution of 11x āˆ’ 6 = āˆ’28 is x = -2.

The lines y = 11x āˆ’ 6 and y = -28 meet at x = -2-8-6-4-224-100-80-60-40-202040x = -2y = 11x āˆ’ 6y = -28
The lines y = 11x āˆ’ 6 and y = -28 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’6=āˆ’2811x - 6 = -28
  2. 2

    Add 6 to both sides:

    11xāˆ’6+6=āˆ’28+6 ⇒ 11x=āˆ’2211x - 6 + 6 = -28 + 6 \ \Rightarrow\ 11x = -22
  3. 3

    Divide both sides by 11:

    11x11=āˆ’2211 ⇒ x=āˆ’2\frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    11ā‹…(āˆ’2)āˆ’6=āˆ’22āˆ’6=āˆ’28āœ“11\cdot(-2) - 6 = -22 - 6 = -28 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 6 = -28\ \Rightarrow\ x = -2 \]
\[ 11x - 6 = -28 \]
\[ 11x - 6 + 6 = -28 + 6 \ \Rightarrow\ 11x = -22 \]
\[ \frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2 \]
\[ 11\cdot(-2) - 6 = -22 - 6 = -28 \checkmark \]

Trying values of x in 11x āˆ’ 6 = āˆ’28

x11x āˆ’ 6Equals -28?
-4-50no
-3-39no
-2-28yes
-1-17no
0-6no

Questions

What is x in 11x āˆ’ 6 = āˆ’28?

The solution of 11x āˆ’ 6 = āˆ’28 is x = -2.

How do you solve 11x āˆ’ 6 = āˆ’28?

Add 6 to both sides to get 11x = -22, then divide both sides by 11 to get x = -2.

How do I check the answer?

Replace x by -2: 11(-2) āˆ’ 6 = -28, which is -28.

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    Solve 11x āˆ’ 6 = āˆ’28: x = -2 (steps and check) | WordGPT