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Solve 11x āˆ’ 5 = 215

The solution of 11x āˆ’ 5 = 215 is x = 20.

The lines y = 11x āˆ’ 5 and y = 215 meet at x = 2014161820222426140160180200220240260280x = 20y = 11x āˆ’ 5y = 215
The lines y = 11x āˆ’ 5 and y = 215 meet at x = 20. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’5=21511x - 5 = 215
  2. 2

    Add 5 to both sides:

    11xāˆ’5+5=215+5 ⇒ 11x=22011x - 5 + 5 = 215 + 5 \ \Rightarrow\ 11x = 220
  3. 3

    Divide both sides by 11:

    11x11=22011 ⇒ x=20\frac{11x}{11} = \frac{220}{11} \ \Rightarrow\ x = 20
  4. 4

    Check: put x = 20 back into the equation.

    11ā‹…20āˆ’5=220āˆ’5=215āœ“11\cdot20 - 5 = 220 - 5 = 215 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 5 = 215\ \Rightarrow\ x = 20 \]
\[ 11x - 5 = 215 \]
\[ 11x - 5 + 5 = 215 + 5 \ \Rightarrow\ 11x = 220 \]
\[ \frac{11x}{11} = \frac{220}{11} \ \Rightarrow\ x = 20 \]
\[ 11\cdot20 - 5 = 220 - 5 = 215 \checkmark \]

Trying values of x in 11x āˆ’ 5 = 215

x11x āˆ’ 5Equals 215?
18193no
19204no
20215yes
21226no
22237no

Questions

What is x in 11x āˆ’ 5 = 215?

The solution of 11x āˆ’ 5 = 215 is x = 20.

How do you solve 11x āˆ’ 5 = 215?

Add 5 to both sides to get 11x = 220, then divide both sides by 11 to get x = 20.

How do I check the answer?

Replace x by 20: 11(20) āˆ’ 5 = 215, which is 215.

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    Solve 11x āˆ’ 5 = 215: x = 20 (steps and check) | WordGPT