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Solve 11x āˆ’ 4 = āˆ’92

The solution of 11x āˆ’ 4 = āˆ’92 is x = -8.

The lines y = 11x āˆ’ 4 and y = -92 meet at x = -8-14-12-10-8-6-4-2-160-140-120-100-80-60-40-20x = -8y = 11x āˆ’ 4y = -92
The lines y = 11x āˆ’ 4 and y = -92 meet at x = -8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’4=āˆ’9211x - 4 = -92
  2. 2

    Add 4 to both sides:

    11xāˆ’4+4=āˆ’92+4 ⇒ 11x=āˆ’8811x - 4 + 4 = -92 + 4 \ \Rightarrow\ 11x = -88
  3. 3

    Divide both sides by 11:

    11x11=āˆ’8811 ⇒ x=āˆ’8\frac{11x}{11} = \frac{-88}{11} \ \Rightarrow\ x = -8
  4. 4

    Check: put x = -8 back into the equation.

    11ā‹…(āˆ’8)āˆ’4=āˆ’88āˆ’4=āˆ’92āœ“11\cdot(-8) - 4 = -88 - 4 = -92 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 4 = -92\ \Rightarrow\ x = -8 \]
\[ 11x - 4 = -92 \]
\[ 11x - 4 + 4 = -92 + 4 \ \Rightarrow\ 11x = -88 \]
\[ \frac{11x}{11} = \frac{-88}{11} \ \Rightarrow\ x = -8 \]
\[ 11\cdot(-8) - 4 = -88 - 4 = -92 \checkmark \]

Trying values of x in 11x āˆ’ 4 = āˆ’92

x11x āˆ’ 4Equals -92?
-10-114no
-9-103no
-8-92yes
-7-81no
-6-70no

Questions

What is x in 11x āˆ’ 4 = āˆ’92?

The solution of 11x āˆ’ 4 = āˆ’92 is x = -8.

How do you solve 11x āˆ’ 4 = āˆ’92?

Add 4 to both sides to get 11x = -88, then divide both sides by 11 to get x = -8.

How do I check the answer?

Replace x by -8: 11(-8) āˆ’ 4 = -92, which is -92.

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    Solve 11x āˆ’ 4 = āˆ’92: x = -8 (steps and check) | WordGPT