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Solve 11x āˆ’ 4 = 40

The solution of 11x āˆ’ 4 = 40 is x = 4.

The lines y = 11x āˆ’ 4 and y = 40 meet at x = 4-2246810-2020406080100x = 4y = 11x āˆ’ 4y = 40
The lines y = 11x āˆ’ 4 and y = 40 meet at x = 4. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’4=4011x - 4 = 40
  2. 2

    Add 4 to both sides:

    11xāˆ’4+4=40+4 ⇒ 11x=4411x - 4 + 4 = 40 + 4 \ \Rightarrow\ 11x = 44
  3. 3

    Divide both sides by 11:

    11x11=4411 ⇒ x=4\frac{11x}{11} = \frac{44}{11} \ \Rightarrow\ x = 4
  4. 4

    Check: put x = 4 back into the equation.

    11ā‹…4āˆ’4=44āˆ’4=40āœ“11\cdot4 - 4 = 44 - 4 = 40 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 4 = 40\ \Rightarrow\ x = 4 \]
\[ 11x - 4 = 40 \]
\[ 11x - 4 + 4 = 40 + 4 \ \Rightarrow\ 11x = 44 \]
\[ \frac{11x}{11} = \frac{44}{11} \ \Rightarrow\ x = 4 \]
\[ 11\cdot4 - 4 = 44 - 4 = 40 \checkmark \]

Trying values of x in 11x āˆ’ 4 = 40

x11x āˆ’ 4Equals 40?
218no
329no
440yes
551no
662no

Questions

What is x in 11x āˆ’ 4 = 40?

The solution of 11x āˆ’ 4 = 40 is x = 4.

How do you solve 11x āˆ’ 4 = 40?

Add 4 to both sides to get 11x = 44, then divide both sides by 11 to get x = 4.

How do I check the answer?

Replace x by 4: 11(4) āˆ’ 4 = 40, which is 40.

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