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Solve 11x āˆ’ 4 = 18

The solution of 11x āˆ’ 4 = 18 is x = 2.

The lines y = 11x āˆ’ 4 and y = 18 meet at x = 2-4-22468-60-40-2020406080x = 2y = 11x āˆ’ 4y = 18
The lines y = 11x āˆ’ 4 and y = 18 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’4=1811x - 4 = 18
  2. 2

    Add 4 to both sides:

    11xāˆ’4+4=18+4 ⇒ 11x=2211x - 4 + 4 = 18 + 4 \ \Rightarrow\ 11x = 22
  3. 3

    Divide both sides by 11:

    11x11=2211 ⇒ x=2\frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    11ā‹…2āˆ’4=22āˆ’4=18āœ“11\cdot2 - 4 = 22 - 4 = 18 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 4 = 18\ \Rightarrow\ x = 2 \]
\[ 11x - 4 = 18 \]
\[ 11x - 4 + 4 = 18 + 4 \ \Rightarrow\ 11x = 22 \]
\[ \frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2 \]
\[ 11\cdot2 - 4 = 22 - 4 = 18 \checkmark \]

Trying values of x in 11x āˆ’ 4 = 18

x11x āˆ’ 4Equals 18?
0-4no
17no
218yes
329no
440no

Questions

What is x in 11x āˆ’ 4 = 18?

The solution of 11x āˆ’ 4 = 18 is x = 2.

How do you solve 11x āˆ’ 4 = 18?

Add 4 to both sides to get 11x = 22, then divide both sides by 11 to get x = 2.

How do I check the answer?

Replace x by 2: 11(2) āˆ’ 4 = 18, which is 18.

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