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Solve 11x āˆ’ 3 = 118

The solution of 11x āˆ’ 3 = 118 is x = 11.

The lines y = 11x āˆ’ 3 and y = 118 meet at x = 116810121416406080100120140160180x = 11y = 11x āˆ’ 3y = 118
The lines y = 11x āˆ’ 3 and y = 118 meet at x = 11. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’3=11811x - 3 = 118
  2. 2

    Add 3 to both sides:

    11xāˆ’3+3=118+3 ⇒ 11x=12111x - 3 + 3 = 118 + 3 \ \Rightarrow\ 11x = 121
  3. 3

    Divide both sides by 11:

    11x11=12111 ⇒ x=11\frac{11x}{11} = \frac{121}{11} \ \Rightarrow\ x = 11
  4. 4

    Check: put x = 11 back into the equation.

    11ā‹…11āˆ’3=121āˆ’3=118āœ“11\cdot11 - 3 = 121 - 3 = 118 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 3 = 118\ \Rightarrow\ x = 11 \]
\[ 11x - 3 = 118 \]
\[ 11x - 3 + 3 = 118 + 3 \ \Rightarrow\ 11x = 121 \]
\[ \frac{11x}{11} = \frac{121}{11} \ \Rightarrow\ x = 11 \]
\[ 11\cdot11 - 3 = 121 - 3 = 118 \checkmark \]

Trying values of x in 11x āˆ’ 3 = 118

x11x āˆ’ 3Equals 118?
996no
10107no
11118yes
12129no
13140no

Questions

What is x in 11x āˆ’ 3 = 118?

The solution of 11x āˆ’ 3 = 118 is x = 11.

How do you solve 11x āˆ’ 3 = 118?

Add 3 to both sides to get 11x = 121, then divide both sides by 11 to get x = 11.

How do I check the answer?

Replace x by 11: 11(11) āˆ’ 3 = 118, which is 118.

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