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Solve 11x āˆ’ 2 = 20

The solution of 11x āˆ’ 2 = 20 is x = 2.

The lines y = 11x āˆ’ 2 and y = 20 meet at x = 2-4-22468-40-2020406080x = 2y = 11x āˆ’ 2y = 20
The lines y = 11x āˆ’ 2 and y = 20 meet at x = 2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’2=2011x - 2 = 20
  2. 2

    Add 2 to both sides:

    11xāˆ’2+2=20+2 ⇒ 11x=2211x - 2 + 2 = 20 + 2 \ \Rightarrow\ 11x = 22
  3. 3

    Divide both sides by 11:

    11x11=2211 ⇒ x=2\frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2
  4. 4

    Check: put x = 2 back into the equation.

    11ā‹…2āˆ’2=22āˆ’2=20āœ“11\cdot2 - 2 = 22 - 2 = 20 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 2 = 20\ \Rightarrow\ x = 2 \]
\[ 11x - 2 = 20 \]
\[ 11x - 2 + 2 = 20 + 2 \ \Rightarrow\ 11x = 22 \]
\[ \frac{11x}{11} = \frac{22}{11} \ \Rightarrow\ x = 2 \]
\[ 11\cdot2 - 2 = 22 - 2 = 20 \checkmark \]

Trying values of x in 11x āˆ’ 2 = 20

x11x āˆ’ 2Equals 20?
0-2no
19no
220yes
331no
442no

Questions

What is x in 11x āˆ’ 2 = 20?

The solution of 11x āˆ’ 2 = 20 is x = 2.

How do you solve 11x āˆ’ 2 = 20?

Add 2 to both sides to get 11x = 22, then divide both sides by 11 to get x = 2.

How do I check the answer?

Replace x by 2: 11(2) āˆ’ 2 = 20, which is 20.

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