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Solve 11x āˆ’ 14 = āˆ’80

The solution of 11x āˆ’ 14 = āˆ’80 is x = -6.

The lines y = 11x āˆ’ 14 and y = -80 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 11x āˆ’ 14y = -80
The lines y = 11x āˆ’ 14 and y = -80 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’14=āˆ’8011x - 14 = -80
  2. 2

    Add 14 to both sides:

    11xāˆ’14+14=āˆ’80+14 ⇒ 11x=āˆ’6611x - 14 + 14 = -80 + 14 \ \Rightarrow\ 11x = -66
  3. 3

    Divide both sides by 11:

    11x11=āˆ’6611 ⇒ x=āˆ’6\frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    11ā‹…(āˆ’6)āˆ’14=āˆ’66āˆ’14=āˆ’80āœ“11\cdot(-6) - 14 = -66 - 14 = -80 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 14 = -80\ \Rightarrow\ x = -6 \]
\[ 11x - 14 = -80 \]
\[ 11x - 14 + 14 = -80 + 14 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) - 14 = -66 - 14 = -80 \checkmark \]

Trying values of x in 11x āˆ’ 14 = āˆ’80

x11x āˆ’ 14Equals -80?
-8-102no
-7-91no
-6-80yes
-5-69no
-4-58no

Questions

What is x in 11x āˆ’ 14 = āˆ’80?

The solution of 11x āˆ’ 14 = āˆ’80 is x = -6.

How do you solve 11x āˆ’ 14 = āˆ’80?

Add 14 to both sides to get 11x = -66, then divide both sides by 11 to get x = -6.

How do I check the answer?

Replace x by -6: 11(-6) āˆ’ 14 = -80, which is -80.

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    Solve 11x āˆ’ 14 = āˆ’80: x = -6 (steps and check) | WordGPT