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Solve 11x āˆ’ 13 = āˆ’68

The solution of 11x āˆ’ 13 = āˆ’68 is x = -5.

The lines y = 11x āˆ’ 13 and y = -68 meet at x = -5-10-8-6-4-2-140-120-100-80-60-40-20x = -5y = 11x āˆ’ 13y = -68
The lines y = 11x āˆ’ 13 and y = -68 meet at x = -5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’13=āˆ’6811x - 13 = -68
  2. 2

    Add 13 to both sides:

    11xāˆ’13+13=āˆ’68+13 ⇒ 11x=āˆ’5511x - 13 + 13 = -68 + 13 \ \Rightarrow\ 11x = -55
  3. 3

    Divide both sides by 11:

    11x11=āˆ’5511 ⇒ x=āˆ’5\frac{11x}{11} = \frac{-55}{11} \ \Rightarrow\ x = -5
  4. 4

    Check: put x = -5 back into the equation.

    11ā‹…(āˆ’5)āˆ’13=āˆ’55āˆ’13=āˆ’68āœ“11\cdot(-5) - 13 = -55 - 13 = -68 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 13 = -68\ \Rightarrow\ x = -5 \]
\[ 11x - 13 = -68 \]
\[ 11x - 13 + 13 = -68 + 13 \ \Rightarrow\ 11x = -55 \]
\[ \frac{11x}{11} = \frac{-55}{11} \ \Rightarrow\ x = -5 \]
\[ 11\cdot(-5) - 13 = -55 - 13 = -68 \checkmark \]

Trying values of x in 11x āˆ’ 13 = āˆ’68

x11x āˆ’ 13Equals -68?
-7-90no
-6-79no
-5-68yes
-4-57no
-3-46no

Questions

What is x in 11x āˆ’ 13 = āˆ’68?

The solution of 11x āˆ’ 13 = āˆ’68 is x = -5.

How do you solve 11x āˆ’ 13 = āˆ’68?

Add 13 to both sides to get 11x = -55, then divide both sides by 11 to get x = -5.

How do I check the answer?

Replace x by -5: 11(-5) āˆ’ 13 = -68, which is -68.

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    Solve 11x āˆ’ 13 = āˆ’68: x = -5 (steps and check) | WordGPT