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Solve 11x āˆ’ 13 = 42

The solution of 11x āˆ’ 13 = 42 is x = 5.

The lines y = 11x āˆ’ 13 and y = 42 meet at x = 5246810-2020406080100120x = 5y = 11x āˆ’ 13y = 42
The lines y = 11x āˆ’ 13 and y = 42 meet at x = 5. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’13=4211x - 13 = 42
  2. 2

    Add 13 to both sides:

    11xāˆ’13+13=42+13 ⇒ 11x=5511x - 13 + 13 = 42 + 13 \ \Rightarrow\ 11x = 55
  3. 3

    Divide both sides by 11:

    11x11=5511 ⇒ x=5\frac{11x}{11} = \frac{55}{11} \ \Rightarrow\ x = 5
  4. 4

    Check: put x = 5 back into the equation.

    11ā‹…5āˆ’13=55āˆ’13=42āœ“11\cdot5 - 13 = 55 - 13 = 42 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 13 = 42\ \Rightarrow\ x = 5 \]
\[ 11x - 13 = 42 \]
\[ 11x - 13 + 13 = 42 + 13 \ \Rightarrow\ 11x = 55 \]
\[ \frac{11x}{11} = \frac{55}{11} \ \Rightarrow\ x = 5 \]
\[ 11\cdot5 - 13 = 55 - 13 = 42 \checkmark \]

Trying values of x in 11x āˆ’ 13 = 42

x11x āˆ’ 13Equals 42?
320no
431no
542yes
653no
764no

Questions

What is x in 11x āˆ’ 13 = 42?

The solution of 11x āˆ’ 13 = 42 is x = 5.

How do you solve 11x āˆ’ 13 = 42?

Add 13 to both sides to get 11x = 55, then divide both sides by 11 to get x = 5.

How do I check the answer?

Replace x by 5: 11(5) āˆ’ 13 = 42, which is 42.

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