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Solve 11x āˆ’ 12 = āˆ’78

The solution of 11x āˆ’ 12 = āˆ’78 is x = -6.

The lines y = 11x āˆ’ 12 and y = -78 meet at x = -6-12-10-8-6-4-2-140-120-100-80-60-40-20x = -6y = 11x āˆ’ 12y = -78
The lines y = 11x āˆ’ 12 and y = -78 meet at x = -6. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’12=āˆ’7811x - 12 = -78
  2. 2

    Add 12 to both sides:

    11xāˆ’12+12=āˆ’78+12 ⇒ 11x=āˆ’6611x - 12 + 12 = -78 + 12 \ \Rightarrow\ 11x = -66
  3. 3

    Divide both sides by 11:

    11x11=āˆ’6611 ⇒ x=āˆ’6\frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6
  4. 4

    Check: put x = -6 back into the equation.

    11ā‹…(āˆ’6)āˆ’12=āˆ’66āˆ’12=āˆ’78āœ“11\cdot(-6) - 12 = -66 - 12 = -78 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 12 = -78\ \Rightarrow\ x = -6 \]
\[ 11x - 12 = -78 \]
\[ 11x - 12 + 12 = -78 + 12 \ \Rightarrow\ 11x = -66 \]
\[ \frac{11x}{11} = \frac{-66}{11} \ \Rightarrow\ x = -6 \]
\[ 11\cdot(-6) - 12 = -66 - 12 = -78 \checkmark \]

Trying values of x in 11x āˆ’ 12 = āˆ’78

x11x āˆ’ 12Equals -78?
-8-100no
-7-89no
-6-78yes
-5-67no
-4-56no

Questions

What is x in 11x āˆ’ 12 = āˆ’78?

The solution of 11x āˆ’ 12 = āˆ’78 is x = -6.

How do you solve 11x āˆ’ 12 = āˆ’78?

Add 12 to both sides to get 11x = -66, then divide both sides by 11 to get x = -6.

How do I check the answer?

Replace x by -6: 11(-6) āˆ’ 12 = -78, which is -78.

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    Solve 11x āˆ’ 12 = āˆ’78: x = -6 (steps and check) | WordGPT