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Solve 11x āˆ’ 12 = 208

The solution of 11x āˆ’ 12 = 208 is x = 20.

The lines y = 11x āˆ’ 12 and y = 208 meet at x = 2014161820222426140160180200220240260280x = 20y = 11x āˆ’ 12y = 208
The lines y = 11x āˆ’ 12 and y = 208 meet at x = 20. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’12=20811x - 12 = 208
  2. 2

    Add 12 to both sides:

    11xāˆ’12+12=208+12 ⇒ 11x=22011x - 12 + 12 = 208 + 12 \ \Rightarrow\ 11x = 220
  3. 3

    Divide both sides by 11:

    11x11=22011 ⇒ x=20\frac{11x}{11} = \frac{220}{11} \ \Rightarrow\ x = 20
  4. 4

    Check: put x = 20 back into the equation.

    11ā‹…20āˆ’12=220āˆ’12=208āœ“11\cdot20 - 12 = 220 - 12 = 208 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 12 = 208\ \Rightarrow\ x = 20 \]
\[ 11x - 12 = 208 \]
\[ 11x - 12 + 12 = 208 + 12 \ \Rightarrow\ 11x = 220 \]
\[ \frac{11x}{11} = \frac{220}{11} \ \Rightarrow\ x = 20 \]
\[ 11\cdot20 - 12 = 220 - 12 = 208 \checkmark \]

Trying values of x in 11x āˆ’ 12 = 208

x11x āˆ’ 12Equals 208?
18186no
19197no
20208yes
21219no
22230no

Questions

What is x in 11x āˆ’ 12 = 208?

The solution of 11x āˆ’ 12 = 208 is x = 20.

How do you solve 11x āˆ’ 12 = 208?

Add 12 to both sides to get 11x = 220, then divide both sides by 11 to get x = 20.

How do I check the answer?

Replace x by 20: 11(20) āˆ’ 12 = 208, which is 208.

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