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Solve 11x āˆ’ 11 = āˆ’22

The solution of 11x āˆ’ 11 = āˆ’22 is x = -1.

The lines y = 11x āˆ’ 11 and y = -22 meet at x = -1-6-4-224-100-80-60-40-202040x = -1y = 11x āˆ’ 11y = -22
The lines y = 11x āˆ’ 11 and y = -22 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’11=āˆ’2211x - 11 = -22
  2. 2

    Add 11 to both sides:

    11xāˆ’11+11=āˆ’22+11 ⇒ 11x=āˆ’1111x - 11 + 11 = -22 + 11 \ \Rightarrow\ 11x = -11
  3. 3

    Divide both sides by 11:

    11x11=āˆ’1111 ⇒ x=āˆ’1\frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    11ā‹…(āˆ’1)āˆ’11=āˆ’11āˆ’11=āˆ’22āœ“11\cdot(-1) - 11 = -11 - 11 = -22 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 11 = -22\ \Rightarrow\ x = -1 \]
\[ 11x - 11 = -22 \]
\[ 11x - 11 + 11 = -22 + 11 \ \Rightarrow\ 11x = -11 \]
\[ \frac{11x}{11} = \frac{-11}{11} \ \Rightarrow\ x = -1 \]
\[ 11\cdot(-1) - 11 = -11 - 11 = -22 \checkmark \]

Trying values of x in 11x āˆ’ 11 = āˆ’22

x11x āˆ’ 11Equals -22?
-3-44no
-2-33no
-1-22yes
0-11no
10no

Questions

What is x in 11x āˆ’ 11 = āˆ’22?

The solution of 11x āˆ’ 11 = āˆ’22 is x = -1.

How do you solve 11x āˆ’ 11 = āˆ’22?

Add 11 to both sides to get 11x = -11, then divide both sides by 11 to get x = -1.

How do I check the answer?

Replace x by -1: 11(-1) āˆ’ 11 = -22, which is -22.

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    Solve 11x āˆ’ 11 = āˆ’22: x = -1 (steps and check) | WordGPT