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Solve 11x āˆ’ 10 = āˆ’32

The solution of 11x āˆ’ 10 = āˆ’32 is x = -2.

The lines y = 11x āˆ’ 10 and y = -32 meet at x = -2-8-6-4-224-100-80-60-40-202040x = -2y = 11x āˆ’ 10y = -32
The lines y = 11x āˆ’ 10 and y = -32 meet at x = -2. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’10=āˆ’3211x - 10 = -32
  2. 2

    Add 10 to both sides:

    11xāˆ’10+10=āˆ’32+10 ⇒ 11x=āˆ’2211x - 10 + 10 = -32 + 10 \ \Rightarrow\ 11x = -22
  3. 3

    Divide both sides by 11:

    11x11=āˆ’2211 ⇒ x=āˆ’2\frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2
  4. 4

    Check: put x = -2 back into the equation.

    11ā‹…(āˆ’2)āˆ’10=āˆ’22āˆ’10=āˆ’32āœ“11\cdot(-2) - 10 = -22 - 10 = -32 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 10 = -32\ \Rightarrow\ x = -2 \]
\[ 11x - 10 = -32 \]
\[ 11x - 10 + 10 = -32 + 10 \ \Rightarrow\ 11x = -22 \]
\[ \frac{11x}{11} = \frac{-22}{11} \ \Rightarrow\ x = -2 \]
\[ 11\cdot(-2) - 10 = -22 - 10 = -32 \checkmark \]

Trying values of x in 11x āˆ’ 10 = āˆ’32

x11x āˆ’ 10Equals -32?
-4-54no
-3-43no
-2-32yes
-1-21no
0-10no

Questions

What is x in 11x āˆ’ 10 = āˆ’32?

The solution of 11x āˆ’ 10 = āˆ’32 is x = -2.

How do you solve 11x āˆ’ 10 = āˆ’32?

Add 10 to both sides to get 11x = -22, then divide both sides by 11 to get x = -2.

How do I check the answer?

Replace x by -2: 11(-2) āˆ’ 10 = -32, which is -32.

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    Solve 11x āˆ’ 10 = āˆ’32: x = -2 (steps and check) | WordGPT