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Solve 11x āˆ’ 10 = 78

The solution of 11x āˆ’ 10 = 78 is x = 8.

The lines y = 11x āˆ’ 10 and y = 78 meet at x = 8246810121420406080100120140x = 8y = 11x āˆ’ 10y = 78
The lines y = 11x āˆ’ 10 and y = 78 meet at x = 8. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.

    11xāˆ’10=7811x - 10 = 78
  2. 2

    Add 10 to both sides:

    11xāˆ’10+10=78+10 ⇒ 11x=8811x - 10 + 10 = 78 + 10 \ \Rightarrow\ 11x = 88
  3. 3

    Divide both sides by 11:

    11x11=8811 ⇒ x=8\frac{11x}{11} = \frac{88}{11} \ \Rightarrow\ x = 8
  4. 4

    Check: put x = 8 back into the equation.

    11ā‹…8āˆ’10=88āˆ’10=78āœ“11\cdot8 - 10 = 88 - 10 = 78 \checkmark
LaTeX source of the formulas on this page
\[ 11x - 10 = 78\ \Rightarrow\ x = 8 \]
\[ 11x - 10 = 78 \]
\[ 11x - 10 + 10 = 78 + 10 \ \Rightarrow\ 11x = 88 \]
\[ \frac{11x}{11} = \frac{88}{11} \ \Rightarrow\ x = 8 \]
\[ 11\cdot8 - 10 = 88 - 10 = 78 \checkmark \]

Trying values of x in 11x āˆ’ 10 = 78

x11x āˆ’ 10Equals 78?
656no
767no
878yes
989no
10100no

Questions

What is x in 11x āˆ’ 10 = 78?

The solution of 11x āˆ’ 10 = 78 is x = 8.

How do you solve 11x āˆ’ 10 = 78?

Add 10 to both sides to get 11x = 88, then divide both sides by 11 to get x = 8.

How do I check the answer?

Replace x by 8: 11(8) āˆ’ 10 = 78, which is 78.

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