Solve 11x − 1 = 164

The solution of 11x − 1 = 164 is x = 15.

11x - 1 = 164\ \Rightarrow\ x = 15

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The lines y = 11x − 1 and y = 164 meet at x = 15. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

1
The goal is to get x alone. Undo the operations in the opposite order: first the subtraction, then the multiplication.
$11x - 1 = 164$
2
Add 1 to both sides:
$11x - 1 + 1 = 164 + 1 \ \Rightarrow\ 11x = 165$
3
Divide both sides by 11:
$\frac{11x}{11} = \frac{165}{11} \ \Rightarrow\ x = 15$
4
Check: put x = 15 back into the equation.
$11\cdot15 - 1 = 165 - 1 = 164 \checkmark$

LaTeX source of the formulas on this page

\[ 11x - 1 = 164\ \Rightarrow\ x = 15 \]
\[ 11x - 1 = 164 \]
\[ 11x - 1 + 1 = 164 + 1 \ \Rightarrow\ 11x = 165 \]
\[ \frac{11x}{11} = \frac{165}{11} \ \Rightarrow\ x = 15 \]
\[ 11\cdot15 - 1 = 165 - 1 = 164 \checkmark \]

Trying values of x in 11x − 1 = 164

x	11x − 1	Equals 164?
13	142	no
14	153	no
15	164	yes
16	175	no
17	186	no

Questions

What is x in 11x − 1 = 164?

The solution of 11x − 1 = 164 is x = 15.

How do you solve 11x − 1 = 164?

Add 1 to both sides to get 11x = 165, then divide both sides by 11 to get x = 15.

How do I check the answer?

Replace x by 15: 11(15) − 1 = 164, which is 164.

Solve 11x − 1 = 164

How to work it out

Trying values of x in 11x − 1 = 164

Questions

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