Solve 10x + 8 = ā62
The solution of 10x + 8 = ā62 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 8 = -62\ \Rightarrow\ x = -7 \]
\[ 10x + 8 = -62 \]
\[ 10x + 8 - 8 = -62 - 8 \ \Rightarrow\ 10x = -70 \]
\[ \frac{10x}{10} = \frac{-70}{10} \ \Rightarrow\ x = -7 \]
\[ 10\cdot(-7) + 8 = -70 + 8 = -62 \checkmark \]Trying values of x in 10x + 8 = ā62
| x | 10x + 8 | Equals -62? |
|---|---|---|
| -9 | -82 | no |
| -8 | -72 | no |
| -7 | -62 | yes |
| -6 | -52 | no |
| -5 | -42 | no |
Questions
What is x in 10x + 8 = ā62?
The solution of 10x + 8 = ā62 is x = -7.
How do you solve 10x + 8 = ā62?
Subtract 8 from both sides to get 10x = -70, then divide both sides by 10 to get x = -7.
How do I check the answer?
Replace x by -7: 10(-7) + 8 = -62, which is -62.