Solve 10x + 8 = ā42
The solution of 10x + 8 = ā42 is x = -5.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 8 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -5 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 8 = -42\ \Rightarrow\ x = -5 \]
\[ 10x + 8 = -42 \]
\[ 10x + 8 - 8 = -42 - 8 \ \Rightarrow\ 10x = -50 \]
\[ \frac{10x}{10} = \frac{-50}{10} \ \Rightarrow\ x = -5 \]
\[ 10\cdot(-5) + 8 = -50 + 8 = -42 \checkmark \]Trying values of x in 10x + 8 = ā42
| x | 10x + 8 | Equals -42? |
|---|---|---|
| -7 | -62 | no |
| -6 | -52 | no |
| -5 | -42 | yes |
| -4 | -32 | no |
| -3 | -22 | no |
Questions
What is x in 10x + 8 = ā42?
The solution of 10x + 8 = ā42 is x = -5.
How do you solve 10x + 8 = ā42?
Subtract 8 from both sides to get 10x = -50, then divide both sides by 10 to get x = -5.
How do I check the answer?
Replace x by -5: 10(-5) + 8 = -42, which is -42.