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Solve 10x + 8 = āˆ’2

The solution of 10x + 8 = āˆ’2 is x = -1.

The lines y = 10x + 8 and y = -2 meet at x = -1-6-4-224-60-40-20204060x = -1y = 10x + 8y = -2
The lines y = 10x + 8 and y = -2 meet at x = -1. The solution of the equation is the x-coordinate of the point where the two sides are equal.

How to work it out

  1. 1

    The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.

    10x+8=āˆ’210x + 8 = -2
  2. 2

    Subtract 8 from both sides:

    10x+8āˆ’8=āˆ’2āˆ’8 ⇒ 10x=āˆ’1010x + 8 - 8 = -2 - 8 \ \Rightarrow\ 10x = -10
  3. 3

    Divide both sides by 10:

    10x10=āˆ’1010 ⇒ x=āˆ’1\frac{10x}{10} = \frac{-10}{10} \ \Rightarrow\ x = -1
  4. 4

    Check: put x = -1 back into the equation.

    10ā‹…(āˆ’1)+8=āˆ’10+8=āˆ’2āœ“10\cdot(-1) + 8 = -10 + 8 = -2 \checkmark
LaTeX source of the formulas on this page
\[ 10x + 8 = -2\ \Rightarrow\ x = -1 \]
\[ 10x + 8 = -2 \]
\[ 10x + 8 - 8 = -2 - 8 \ \Rightarrow\ 10x = -10 \]
\[ \frac{10x}{10} = \frac{-10}{10} \ \Rightarrow\ x = -1 \]
\[ 10\cdot(-1) + 8 = -10 + 8 = -2 \checkmark \]

Trying values of x in 10x + 8 = āˆ’2

x10x + 8Equals -2?
-3-22no
-2-12no
-1-2yes
08no
118no

Questions

What is x in 10x + 8 = āˆ’2?

The solution of 10x + 8 = āˆ’2 is x = -1.

How do you solve 10x + 8 = āˆ’2?

Subtract 8 from both sides to get 10x = -10, then divide both sides by 10 to get x = -1.

How do I check the answer?

Replace x by -1: 10(-1) + 8 = -2, which is -2.

Similar equations

    Solve 10x + 8 = āˆ’2: x = -1 (steps and check) | WordGPT