Solve 10x + 2 = ā78
The solution of 10x + 2 = ā78 is x = -8.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -8 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 2 = -78\ \Rightarrow\ x = -8 \]
\[ 10x + 2 = -78 \]
\[ 10x + 2 - 2 = -78 - 2 \ \Rightarrow\ 10x = -80 \]
\[ \frac{10x}{10} = \frac{-80}{10} \ \Rightarrow\ x = -8 \]
\[ 10\cdot(-8) + 2 = -80 + 2 = -78 \checkmark \]Trying values of x in 10x + 2 = ā78
| x | 10x + 2 | Equals -78? |
|---|---|---|
| -10 | -98 | no |
| -9 | -88 | no |
| -8 | -78 | yes |
| -7 | -68 | no |
| -6 | -58 | no |
Questions
What is x in 10x + 2 = ā78?
The solution of 10x + 2 = ā78 is x = -8.
How do you solve 10x + 2 = ā78?
Subtract 2 from both sides to get 10x = -80, then divide both sides by 10 to get x = -8.
How do I check the answer?
Replace x by -8: 10(-8) + 2 = -78, which is -78.