Solve 10x + 2 = 192
The solution of 10x + 2 = 192 is x = 19.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 2 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = 19 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 2 = 192\ \Rightarrow\ x = 19 \]
\[ 10x + 2 = 192 \]
\[ 10x + 2 - 2 = 192 - 2 \ \Rightarrow\ 10x = 190 \]
\[ \frac{10x}{10} = \frac{190}{10} \ \Rightarrow\ x = 19 \]
\[ 10\cdot19 + 2 = 190 + 2 = 192 \checkmark \]Trying values of x in 10x + 2 = 192
| x | 10x + 2 | Equals 192? |
|---|---|---|
| 17 | 172 | no |
| 18 | 182 | no |
| 19 | 192 | yes |
| 20 | 202 | no |
| 21 | 212 | no |
Questions
What is x in 10x + 2 = 192?
The solution of 10x + 2 = 192 is x = 19.
How do you solve 10x + 2 = 192?
Subtract 2 from both sides to get 10x = 190, then divide both sides by 10 to get x = 19.
How do I check the answer?
Replace x by 19: 10(19) + 2 = 192, which is 192.