Solve 10x + 15 = ā55
The solution of 10x + 15 = ā55 is x = -7.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 15 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -7 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 15 = -55\ \Rightarrow\ x = -7 \]
\[ 10x + 15 = -55 \]
\[ 10x + 15 - 15 = -55 - 15 \ \Rightarrow\ 10x = -70 \]
\[ \frac{10x}{10} = \frac{-70}{10} \ \Rightarrow\ x = -7 \]
\[ 10\cdot(-7) + 15 = -70 + 15 = -55 \checkmark \]Trying values of x in 10x + 15 = ā55
| x | 10x + 15 | Equals -55? |
|---|---|---|
| -9 | -75 | no |
| -8 | -65 | no |
| -7 | -55 | yes |
| -6 | -45 | no |
| -5 | -35 | no |
Questions
What is x in 10x + 15 = ā55?
The solution of 10x + 15 = ā55 is x = -7.
How do you solve 10x + 15 = ā55?
Subtract 15 from both sides to get 10x = -70, then divide both sides by 10 to get x = -7.
How do I check the answer?
Replace x by -7: 10(-7) + 15 = -55, which is -55.