Solve 10x + 11 = ā19
The solution of 10x + 11 = ā19 is x = -3.
How to work it out
- 1
The goal is to get x alone. Undo the operations in the opposite order: first the addition, then the multiplication.
- 2
Subtract 11 from both sides:
- 3
Divide both sides by 10:
- 4
Check: put x = -3 back into the equation.
LaTeX source of the formulas on this page
\[ 10x + 11 = -19\ \Rightarrow\ x = -3 \]
\[ 10x + 11 = -19 \]
\[ 10x + 11 - 11 = -19 - 11 \ \Rightarrow\ 10x = -30 \]
\[ \frac{10x}{10} = \frac{-30}{10} \ \Rightarrow\ x = -3 \]
\[ 10\cdot(-3) + 11 = -30 + 11 = -19 \checkmark \]Trying values of x in 10x + 11 = ā19
| x | 10x + 11 | Equals -19? |
|---|---|---|
| -5 | -39 | no |
| -4 | -29 | no |
| -3 | -19 | yes |
| -2 | -9 | no |
| -1 | 1 | no |
Questions
What is x in 10x + 11 = ā19?
The solution of 10x + 11 = ā19 is x = -3.
How do you solve 10x + 11 = ā19?
Subtract 11 from both sides to get 10x = -30, then divide both sides by 10 to get x = -3.
How do I check the answer?
Replace x by -3: 10(-3) + 11 = -19, which is -19.